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5a^2=73=3
We move all terms to the left:
5a^2-(73)=0
a = 5; b = 0; c = -73;
Δ = b2-4ac
Δ = 02-4·5·(-73)
Δ = 1460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1460}=\sqrt{4*365}=\sqrt{4}*\sqrt{365}=2\sqrt{365}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{365}}{2*5}=\frac{0-2\sqrt{365}}{10} =-\frac{2\sqrt{365}}{10} =-\frac{\sqrt{365}}{5} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{365}}{2*5}=\frac{0+2\sqrt{365}}{10} =\frac{2\sqrt{365}}{10} =\frac{\sqrt{365}}{5} $
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